Use ΔG° = -RT ln K with R = 8.314 J/(mol·K).
A reaction has ΔG° = -10. kJ/mol at 298 K. What does this imply for K?
- A
K < 1
- Bcheck_circle
K > 1
- C
K = 1
- D
K = 0
Explanation
ΔG° = -RT ln K; negative ΔG° gives ln K > 0, so K > 1 and products are favored.