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Collision Model

AP Chemistry· difficulty 4/5

A reaction's rate constant doubles when temperature increases from 300 K to 310 K. What is the activation energy?

  • A

    Ea≈53.6E_a \approx 53.6 kJ/mol

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  • B

    Ea≈110E_a \approx 110 kJ/mol

  • C

    Ea≈8.31E_a \approx 8.31 kJ/mol

  • D

    Ea≈26.8E_a \approx 26.8 kJ/mol

Explanation

ln⁡(k2/k1)=−Ea/R(1/T2−1/T1)\ln(k_2/k_1) = -E_a/R(1/T_2 - 1/T_1). ln⁡2\ln 2 = 0.693 = Ea/8.314×(1/300−1/310)E_a/8.314 \times (1/300 - 1/310) = Ea/8.314×(1.075×10−4)E_a/8.314 \times (1.075\times 10^{-4}). EaE_a = 0.693×\times8.314/1.075e-4 = 53590 J = 53.6 kJ/mol.

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