H2 + I2 <-> 2 HI, Kc = 64 at equilibrium starting from the initial concentrations shown.
Solve for x.
- A
8.0
- Bcheck_circle
0.80
- C
0.50
- D
1.0
Explanation
Kc = (2x)^2 / (1-x)^2 = 64. Take square root: 2x/(1-x) = 8, so 2x = 8 - 8x, 10x = 8, x = 0.80.
Calculating Equilibrium Concentrations
AP Chemistry· difficulty 4/5
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