From ΔG° = -RT ln K, what is ΔG° when K = 1?
- A
ΔG° < 0
- B
Indeterminate without T
- C
ΔG° > 0
- Dcheck_circle
ΔG° = 0
Explanation
ln(1) = 0, so ΔG° = -RT(0) = 0 regardless of T.
AP Chemistry· difficulty 3/5
From ΔG° = -RT ln K, what is ΔG° when K = 1?
ΔG° < 0
Indeterminate without T
ΔG° > 0
ΔG° = 0
Explanation
ln(1) = 0, so ΔG° = -RT(0) = 0 regardless of T.
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