For Q > 1, why does the Nernst plot show E decreasing as T increases?
- A
Because Faraday's constant decreases
- Bcheck_circle
Because (RT/nF) ln Q grows with T when Q > 1
- C
Because E° decreases with T
- D
Because n increases with T
Explanation
With Q>1, ln Q>0 and (RT/nF)·ln Q rises with T, so E = E° − (RT/nF)ln Q falls.