A plot of 1/[A] vs t produces a straight line with positive slope.
The reaction is best described as which order, and what does the slope represent?
- A
Second order; slope = -k
- B
Zero order; slope = k
- Ccheck_circle
Second order; slope = k
- D
First order; slope = -k
Explanation
For second-order: 1/[A] = 1/[A]0 + kt, so a linear plot with positive slope = k.