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Cell Potential Under Nonstandard Conditions

AP Chemistry· difficulty 4/5

For Cu|Cu2+^{2+}(0.010 M)||Cu2+^{2+}(1.0 M)|Cu (concentration cell), E°cell is 0. The actual EMF at 25°C is

  • A

    0 V

  • B

    +0.059 V (Nernst with log⁡(1.0/0.010)/2\log(1.0/0.010)/2)

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  • C

    +0.029 V

  • D

    +0.118 V

Explanation

E=E°−(0.0592/n)log⁡QE = E° − (0.0592/n)\log Q. Concentration cell: Q=[anode]/[cathode]=0.010/1.0=0.010Q = [\text{anode}]/[\text{cathode}] = 0.010/1.0 = 0.010. E=0−(0.0592/2)log⁡(0.010)=−(0.0296)(−2)=0.0592E = 0 − (0.0592/2)\log(0.010) = −(0.0296)(−2) = 0.0592 V.

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