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Electrolysis and Faraday's Law

AP Chemistry· difficulty 4/5

Current of 1.93 A for 1000 s deposits how many moles of Ag from Ag⁺?

  • A

    0.01

  • B

    0.02

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  • C

    0.10

  • D

    0.20

Explanation

Q = It = 1930 C; mol e⁻ = Q/F = 0.020 → mol Ag = 0.020 (1:1).

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