A compound has empirical formula CH₂O and molar mass ~180 g/mol. Its molecular formula is
- A
C₃H₆O₃
- B
CH₂O
- Ccheck_circle
C₆H₁₂O₆
- D
C₂H₄O₂
Explanation
Empirical mass = 30 g/mol. 180/30 = 6 → multiply each subscript by 6: C₆H₁₂O₆ (e.g., glucose).
Elemental Composition of Pure Substances
AP Chemistry· difficulty 3/5
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