school
Acemy

Henderson-Hasselbalch Equation

AP Chemistry· difficulty 4/5

A buffer is prepared with 0.20 M NH₃ and 0.10 M NH₄Cl. Kb=1.8×10−5K_b = 1.8 \times 10^{-5} for NH₃. The pH is approximately

  • A

    8.968.96

  • B

    9.569.56

    check_circle
  • C

    10.2610.26

  • D

    4.744.74

Explanation

pKa(NH₄⁺) = 14 - pKb = 14 - 4.74 = 9.26. pH = pKa + log([base]/[acid]) = 9.26 + log(0.20/0.10) = 9.26 + 0.30 = 9.56.

Want 10 more like this — adaptive to your weak spots?

Practice 10 like thisarrow_forwardPredict my AP score

Related questions

auto_awesomeAll Toolsquestion_answerHomework Q&Amenu_bookAP & SAT PreptimelineLearn Mode