Henderson-Hasselbalch Equation

AP Chemistry· difficulty 3/5

pH of a buffer is given by

A
$pH = pKa - [A⁻]/[HA]$
B
$pH = pKb + log([A⁻]/[HA])$
C
$pH = pKa + log([HA]/[A⁻])$
D
$pH = pKa + log([A⁻]/[HA])$
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Explanation

Henderson-Hasselbalch: pH = pKa + log([base]/[acid]).

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