Evaluate limx→0(x+2)2−4x\displaystyle\lim_{x\to 0}\dfrac{(x+2)^2 - 4}{x}x→0limx(x+2)2−4.A222B∞\infty∞C444check_circleD000ExplanationExpand: (x+2)2−4=x2+4x+4−4=x2+4x(x+2)^2 - 4 = x^2 + 4x + 4 - 4 = x^2 + 4x(x+2)2−4=x2+4x+4−4=x2+4x. Divide by xxx: x+4→4x + 4 \to 4x+4→4.