Evaluate \displaystyle\lim{x \to -1}\dfrac{x^2 + 3x + 2}{x + 1}.

1 x^2 + 3x + 2 = (x+1)(x+2). Cancel: \lim{x \to -1}(x+2) = 1.

Determining Limits Using Algebraic Manipulation

AP Calculus AB· difficulty 2/5

\displaystyle\lim_{x \to -1}\dfrac{x^2 + 3x + 2}{x + 1}

Explanation

x^2 + 3x + 2 = (x+1)(x+2)

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