Evaluate limx→5x2−25x2−6x+5\displaystyle\lim_{x\to 5}\dfrac{x^2 - 25}{x^2 - 6x + 5}x→5limx2−6x+5x2−25.A111BDoes not existC52\tfrac{5}{2}25check_circleD25\tfrac{2}{5}52ExplanationTop: (x−5)(x+5)(x-5)(x+5)(x−5)(x+5). Bottom: (x−5)(x−1)(x-5)(x-1)(x−5)(x−1). Cancel: (x+5)/(x−1)(x+5)/(x-1)(x+5)/(x−1). At x=5x = 5x=5: 10/4=5/210/4 = 5/210/4=5/2.