Fundamental Theorem of Calculus and Accumulation Functions

AP Calculus AB· difficulty 3/5

Let g(x)=1xt2dtg(x) = \int_1^x t^2\,dt. Then g(2)=g(2) =

  • A

    33

  • B

    13\tfrac{1}{3}

  • C

    88

  • D

    73\tfrac{7}{3}

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Explanation

g(2)=[t3/3]12=8/31/3=7/3g(2) = [t^3/3]_1^2 = 8/3 - 1/3 = 7/3.

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