AP Calculus AB · Topic 6.4

Fundamental Theorem of Calculus and Accumulation Functions Practice

Part of Integration and Accumulation of Change.(FUN-5.D)

Practice questions

9

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Sample questions

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  1. Sample 1difficulty 2/5

    The Fundamental Theorem (Part 1) says ddxaxf(t)dt=\dfrac{d}{dx}\int_a^x f(t)\,dt =

    • A

      f(x)f(x)

      check_circle
    • B

      F(x)F(a)F(x) - F(a)

    • C

      f\int f'

    • D

      f(x)f'(x)

    Why

    Differentiation undoes integration.

  2. Sample 2difficulty 3/5

    t f 2

    Let F(x)=0xf(t)dtF(x) = \int_0^x f(t)\,dt where ff is shown. FF has a relative maximum at x=x =:

    • A

      00

    • B

      22

      check_circle
    • C

      Nowhere

    • D

      44

    Why

    F(x)=f(x)F'(x) = f(x). Since ff changes from positive to negative at x=2x=2, FF has a relative maximum there.

  3. Sample 3difficulty 3/5

    Let g(x)=1xt2dtg(x) = \int_1^x t^2\,dt. Then g(2)=g(2) =

    • A

      33

    • B

      13\tfrac{1}{3}

    • C

      88

    • D

      73\tfrac{7}{3}

      check_circle

    Why

    g(2)=[t3/3]12=8/31/3=7/3g(2) = [t^3/3]_1^2 = 8/3 - 1/3 = 7/3.

  4. Sample 4difficulty 3/5

    For g(x)=2exlntdtg(x) = \int_2^{e^x} \ln t\,dt, g(x)=g'(x) =

    • A

      ln(ex)\ln(e^x)

    • B

      exln(ex)=xexe^x \ln(e^x) = x e^x

      check_circle
    • C

      xexx e^x

    • D

      xexx \cdot e^x

    Why

    Chain rule: ln(ex)ex=xex\ln(e^x) \cdot e^x = x e^x.

  5. Sample 5difficulty 3/5

    The shaded area to the left of x=cx = c represents

    • A

      F(c)=acf(t)dtF(c) = \int_a^c f(t)\,dt

      check_circle
    • B

      f(c)f(c)

    • C

      f(c)f'(c)

    • D

      F(b)F(c)F(b) - F(c)

    Why

    Accumulation function: integral from start to cc.