Fundamental Theorem of Calculus and Accumulation Functions

AP Calculus AB· difficulty 3/5

t f 2

Let F(x)=0xf(t)dtF(x) = \int_0^x f(t)\,dt where ff is shown. FF has a relative maximum at x=x =:

  • A

    00

  • B

    22

    check_circle
  • C

    Nowhere

  • D

    44

Explanation

F(x)=f(x)F'(x) = f(x). Since ff changes from positive to negative at x=2x=2, FF has a relative maximum there.

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