Integration by Substitution

AP Calculus AB· difficulty 2/5

5(2x+1)4dx=\displaystyle\int 5(2x+1)^4\,dx =

  • A

    5(2x+1)55+C\dfrac{5(2x+1)^5}{5} + C

  • B

    5(2x+1)510+C\dfrac{5(2x+1)^5}{10} + C

  • C

    (2x+1)52+C\dfrac{(2x+1)^5}{2} + C

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  • D

    (2x+1)52+C\dfrac{(2x+1)^5}{2} + C

Explanation

u=2x+1u = 2x+1, du=2dxdu = 2\,dx. 5u4du/2=5u5/10=u5/25 \int u^4\,du/2 = 5 u^5/10 = u^5/2.

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