Integration by Substitution

AP Calculus AB· difficulty 2/5

2x(x2+1)3dx=\displaystyle\int 2x(x^2 + 1)^3\,dx =

  • A

    (x2+1)4+C(x^2+1)^4 + C

  • B

    x44+C\dfrac{x^4}{4} + C

  • C

    (x2+1)33+C\dfrac{(x^2+1)^3}{3} + C

  • D

    (x2+1)44+C\dfrac{(x^2+1)^4}{4} + C

    check_circle

Explanation

u=x2+1u = x^2 + 1, du=2xdxdu = 2x\,dx. u3du=u4/4\int u^3\,du = u^4/4.

Want 10 more like this — adaptive to your weak spots?

Related questions