x For ∫2xcos(x2) dx\int 2x \cos(x^2)\,dx∫2xcos(x2)dx, the appropriate substitution is:Au=x2u = x^2u=x2check_circleBu=2xu = 2xu=2xCu=cosxu = \cos xu=cosxDu=xu = xu=xExplanationLet u=x2u = x^2u=x2, du=2x dxdu = 2x\,dxdu=2xdx, giving ∫cosu du\int \cos u\,du∫cosudu.