FTC and Definite Integrals

AP Calculus AB· difficulty 2/5

\displaystyle\int_0^{\pi/2} \cos x\,dx =

A
$1$
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B
$0$
C
$\pi/2$
D
$\tfrac{1}{2}$

Explanation

[\sin x]_0^{\pi/2} = 1

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