FTC and Definite Integrals

AP Calculus AB· difficulty 4/5

x

If G(x)=ax2f(t)dtG(x) = \int_a^{x^2} f(t)\,dt, then G(x)G'(x) equals:

  • A

    f(x2)f(x^2)

  • B

    f(x2)2xf(x^2) \cdot 2x

    check_circle
  • C

    2xf(x)2x f(x)

  • D

    f(x)f(x)

Explanation

By FTC and chain rule, G(x)=f(x2)ddx(x2)=2xf(x2)G'(x) = f(x^2) \cdot \frac{d}{dx}(x^2) = 2x f(x^2).

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