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FTC and Definite Integrals

AP Calculus AB· difficulty 2/5

Given ∫14f=5\int_1^4 f = 5 and ∫47f=−3\int_4^7 f = -3, ∫17f=\int_1^7 f =

  • A

    88

  • B

    −15-15

  • C

    1515

  • D

    22

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Explanation

∫17=∫14+∫47=5+(−3)=2\int_1^7 = \int_1^4 + \int_4^7 = 5 + (-3) = 2.

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