The average value of f(x) = x^2 on [0, 3] is

3 \bar f = \frac{1}{3}\int0^3 x^2\,dx = \frac{1}{3}\cdot 9 = 3.

Average Value of a Function on an Interval

AP Calculus AB· difficulty 4/5

f(x) = x^2

Explanation

\bar f = \frac{1}{3}\int_0^3 x^2\,dx = \frac{1}{3}\cdot 9 = 3

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