school
Acemy

Average Value of a Function on an Interval

AP Calculus AB· difficulty 4/5

The average value of f(x)=exf(x) = e^x on [0,1][0, 1] is

  • A

    11

  • B

    ee

  • C

    e−1e - 1

    check_circle
  • D

    e+12\frac{e+1}{2}

Explanation

fˉ=∫01ex dx/1=[ex]01=e−1\bar f = \int_0^1 e^x \, dx / 1 = [e^x]_0^1 = e - 1.

Want 10 more like this — adaptive to your weak spots?

Practice 10 like thisarrow_forwardPredict my AP score

Related questions

auto_awesomeAll Toolsquestion_answerHomework Q&Amenu_bookAP & SAT PreptimelineLearn Mode