Average value of exe^xex on [0,1][0, 1][0,1]:Ae−1e - 1e−1check_circleBe+12\dfrac{e + 1}{2}2e+1Ce/2e/2e/2D111Explanation∫01ex dx/(1)=e−1\int_0^1 e^x\,dx/(1) = e - 1∫01exdx/(1)=e−1.