∫−12∣x∣ dx=\displaystyle \int_{-1}^{2} |x|\, dx =∫−12∣x∣dx=A333B222C32\frac{3}{2}23D52\frac{5}{2}25check_circleExplanationSplit at 0: ∫−10(−x) dx+∫02x dx=1/2+2=5/2\int_{-1}^0(-x)\,dx + \int_0^2 x\,dx = 1/2 + 2 = 5/2∫−10(−x)dx+∫02xdx=1/2+2=5/2.