FTC and Definite Integrals

AP Calculus AB· difficulty 4/5

\displaystyle \int_0^{\pi} \sin x \, dx =

A
$1$
B
$2$
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C
$0$
D
$\pi$

Explanation

[-\cos x]_0^{\pi} = -\cos\pi + \cos 0 = 1 + 1 = 2

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