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Straight-Line Motion: Position, Velocity, Acceleration

AP Calculus AB· difficulty 2/5

A particle's position is s(t)=16−t2s(t) = 16 - t^2 (meters, seconds). Its velocity at t=3t = 3 is

  • A

    +6 m/s+6~\text{m/s}

  • B

    00

  • C

    +9 m/s+9~\text{m/s}

  • D

    −6 m/s-6~\text{m/s}

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Explanation

s′(t)=−2ts'(t) = -2t. At t=3t=3: −6 m/s-6~\text{m/s}.

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