For s(t)=t3−6t2s(t) = t^3 - 6t^2s(t)=t3−6t2, the acceleration at t=1t = 1t=1 isA−12-12−12B121212C−6-6−6check_circleD666Explanationv(t)=3t2−12tv(t) = 3t^2 - 12tv(t)=3t2−12t, a(t)=6t−12a(t) = 6t - 12a(t)=6t−12. At t=1t = 1t=1: −6-6−6.