Straight-Line Motion: Position, Velocity, Acceleration

AP Calculus AB· difficulty 2/5

For s(t)=t36t2s(t) = t^3 - 6t^2, the acceleration at t=1t = 1 is

  • A

    12-12

  • B

    1212

  • C

    6-6

    check_circle
  • D

    66

Explanation

v(t)=3t212tv(t) = 3t^2 - 12t, a(t)=6t12a(t) = 6t - 12. At t=1t = 1: 6-6.

Want 10 more like this — adaptive to your weak spots?

Related questions