Differentiating Inverse Trig Functions

AP Calculus AB· difficulty 2/5

\dfrac{d}{dx}\arctan(2x) =

A
$\dfrac{1}{1+4x^2}$
B
$\dfrac{2x}{1+4x^2}$
C
$\dfrac{2}{1+x^2}$
D
$\dfrac{2}{1+4x^2}$
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Explanation

\dfrac{1}{1+(2x)^2} \cdot 2 = \dfrac{2}{1+4x^2}

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