Differentiating Inverse Trig Functions

AP Calculus AB· difficulty 3/5

\dfrac{d}{dx}\arctan(x^2) =

A
$\dfrac{1}{1 + x^4}$
B
$\dfrac{2x}{1 + x^4}$
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C
$\dfrac{2x}{(1 + x^2)^2}$
D
$\dfrac{2}{1 + x^2}$

Explanation

\dfrac{1}{1 + (x^2)^2} \cdot 2x = \dfrac{2x}{1 + x^4}

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