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Differentiating Inverse Trig Functions

AP Calculus AB· difficulty 2/5

ddxarcsin⁡x=\dfrac{d}{dx}\arcsin x =

  • A

    11−x2\dfrac{1}{\sqrt{1-x^2}}

    check_circle
  • B

    1cos⁡x\dfrac{1}{\cos x}

  • C

    −11−x2\dfrac{-1}{\sqrt{1-x^2}}

  • D

    11+x2\dfrac{1}{1+x^2}

Explanation

Standard inverse trig derivative.

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