L'Hôpital's Rule

AP Calculus AB· difficulty 3/5

\displaystyle\lim_{x\to\infty}\dfrac{x^2}{e^x}

A
$1$
B
$\infty$
C
$0$
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D
$e$

Explanation

2x/e^x \to 2/e^x \to 0

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