Evaluate limx→1x3−1x2−1\displaystyle\lim_{x\to 1}\dfrac{x^3 - 1}{x^2 - 1}x→1limx2−1x3−1.A111B333C32\tfrac{3}{2}23check_circleD222ExplanationL'Hôpital: 3x2/(2x)=3x/2→3/23x^2/(2x) = 3x/2 \to 3/23x2/(2x)=3x/2→3/2 at x=1x = 1x=1.