Evaluate limx→0+xlnx\displaystyle\lim_{x\to 0^+} x \ln xx→0+limxlnx.A000check_circleB111C−1-1−1D−∞-\infty−∞ExplanationRewrite as lnx/(1/x)\ln x/(1/x)lnx/(1/x), ∞/∞\infty/\infty∞/∞ at x→0+x \to 0^+x→0+? Actually −∞/∞-\infty/\infty−∞/∞. L'Hôpital: (1/x)/(−1/x2)=−x→0(1/x)/(-1/x^2) = -x \to 0(1/x)/(−1/x2)=−x→0.