Hardy-Weinberg Equilibrium

AP Biology· difficulty 3/5

Continuing the previous: what fraction of the population is heterozygous (Aa)?

A
$0.84$
B
$0.16$
C
$0.36$
D
$0.48$
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Explanation

2pq = 2(0.6)(0.4) = 0.48 \to 48% are heterozygous.

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