Rotational Equilibrium and Newton's First Law in Rotational Form

AP Physics 1· difficulty 3/5

A beam is hinged at one end and hangs vertically. A horizontal force FF is applied at its other end, LL from the hinge. The torque about the hinge is

  • A

    FL/2F L/2

  • B

    FLsin0F L \sin 0^\circ

  • C

    00

  • D

    FLF L

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Explanation

τ=rFsinθ\tau = r F \sin\theta. The angle between the (vertical) lever and the (horizontal) force is 9090^\circ, so sinθ=1\sin\theta = 1: τ=FL\tau = F L.

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