A uniform 4.0 m beam of mass 10 kg is supported by a pivot 1.0 m from one end. To balance, what mass should be hung at the closer end? ( m/s²; treat beam center at 2.0 m from short end)
- A
40 kg
- B
5 kg
- C
20 kg
- Dcheck_circle
10 kg
Explanation
Beam center of mass is 2.0 m from each end, so it sits 1.0 m on the FAR side of the pivot. Beam weight produces N·m of torque about the pivot. The mass at the short end sits 1.0 m on the opposite side. Balance: N·m, so kg.