A uniform 20 ext{kg} horizontal beam of length L = 4 ext{m} is hinged at its left end. A vertical rope at the right end supports it, and a 40 ext{kg} weight hangs from the midpoint. Using g \approx 10 ext{m/s}^2, what is the tension in the rope?

Question

A uniform 20	ext{kg} horizontal beam of length L = 4	ext{m} is hinged at its left end. A vertical rope at the right end supports it, and a 40	ext{kg} weight hangs from the midpoint. Using g \approx 10	ext{m/s}^2, what is the tension in the rope?

Accepted Answer

300	ext{N}

Torques about the hinge: T \cdot L = (m	ext{beam} g)(L/2) + (m	ext{w} g)(L/2). So T = (20 \cdot 10 + 40 \cdot 10)/2 = 600/2 = 300	ext{N}.

Answer

200	ext{N}

Answer

300	ext{N}

Answer

400	ext{N}

Answer

600	ext{N}

Rotational Equilibrium and Newton's First Law in Rotational Form

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