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AP Physics 1· difficulty 2/5

A motor lifts 50 kg50~\text{kg} at constant 0.40 m/s0.40~\text{m/s}. Using g≈10 m/s2g \approx 10~\text{m/s}^2, the motor's mechanical power output is

  • A

    2000 W2000~\text{W}

  • B

    20 W20~\text{W}

  • C

    500 W500~\text{W}

  • D

    200 W200~\text{W}

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Explanation

P=Fv=mgv=(50)(10)(0.40)=200 WP = F v = m g v = (50)(10)(0.40) = 200~\text{W}.

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