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Power

AP Physics 1· difficulty 2/5

A locomotive applies 40,000 N40{,}000~\text{N} tractive force at constant 25 m/s25~\text{m/s}. Its power output is

  • A

    1600 W1600~\text{W}

  • B

    106 W10^6~\text{W}

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  • C

    109 W10^9~\text{W}

  • D

    105 W10^5~\text{W}

Explanation

P=Fv=(40,000)(25)=1.0×106 WP = F v = (40{,}000)(25) = 1.0 \times 10^6~\text{W}.

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