AP Physics 1 · Topic 3.5

Power Practice

Part of Work, Energy, and Power.(TOP-3.E)

Practice questions

15

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Sample questions

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  1. Sample 1difficulty 1/5

    Two motors do the same total work but motor B takes half the time of motor A. The ratio PB/PAP_B/P_A is

    • A

      1/21/2

    • B

      11

    • C

      22

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    • D

      44

    Why

    P=W/tP = W/t. Same work, half time → twice the power.

  2. Sample 2difficulty 1/5

    An engine performs 6000 J6000~\text{J} of work in 30 s30~\text{s}. What is its average power output?

    • A

      1800 W1800~\text{W}

    • B

      50 W50~\text{W}

    • C

      200 W200~\text{W}

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    • D

      500 W500~\text{W}

    Why

    P=W/t=6000/30=200 WP = W/t = 6000/30 = 200~\text{W}.

  3. Sample 3difficulty 2/5

    Engine A delivers 200 W200~\text{W} for 10 s10~\text{s}. Engine B delivers 400 W400~\text{W} for 10 s10~\text{s}. Engine B does work

    • A

      Four times A

    • B

      Twice A

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    • C

      Same as A

    • D

      Half of A

    Why

    W=PtW = P t. Same time, double power → double work.

  4. Sample 4difficulty 2/5

    A motor lifts 50 kg50~\text{kg} at constant 0.40 m/s0.40~\text{m/s}. Using g10 m/s2g \approx 10~\text{m/s}^2, the motor's mechanical power output is

    • A

      2000 W2000~\text{W}

    • B

      20 W20~\text{W}

    • C

      500 W500~\text{W}

    • D

      200 W200~\text{W}

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    Why

    P=Fv=mgv=(50)(10)(0.40)=200 WP = F v = m g v = (50)(10)(0.40) = 200~\text{W}.

  5. Sample 5difficulty 2/5

    A locomotive applies 40,000 N40{,}000~\text{N} tractive force at constant 25 m/s25~\text{m/s}. Its power output is

    • A

      1600 W1600~\text{W}

    • B

      106 W10^6~\text{W}

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    • C

      109 W10^9~\text{W}

    • D

      105 W10^5~\text{W}

    Why

    P=Fv=(40,000)(25)=1.0×106 WP = F v = (40{,}000)(25) = 1.0 \times 10^6~\text{W}.