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Change in Momentum and Impulse

AP Physics 1· difficulty 2/5

For the same ball above, if it instead <strong>rebounds</strong> elastically at 6 m/s6~\text{m/s}, the impulse from the wall is

  • A

    00

  • B

    12 N⋅s12~\text{N·s}

  • C

    6 N⋅s6~\text{N·s}

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  • D

    3 N⋅s3~\text{N·s}

Explanation

Δp=(0.5)(−6)−(0.5)(6)=−6 kg⋅m/s\Delta p = (0.5)(-6) - (0.5)(6) = -6~\text{kg·m/s} (impulse magnitude 6 N⋅s6~\text{N·s} — twice the absorption case).

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