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Change in Momentum and Impulse

AP Physics 1· difficulty 2/5

A 0.50 kg0.50~\text{kg} ball falls from rest for 2.0 s2.0~\text{s}. The impulse delivered by gravity (using g≈10 m/s2g \approx 10~\text{m/s}^2) is

  • A

    10 N⋅s10~\text{N·s}

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  • B

    20 N⋅s20~\text{N·s}

  • C

    5.0 N⋅s5.0~\text{N·s}

  • D

    1.0 N⋅s1.0~\text{N·s}

Explanation

J=mgt=(0.50)(10)(2.0)=10 N⋅sJ = m g t = (0.50)(10)(2.0) = 10~\text{N·s}.

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