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Change in Momentum and Impulse

AP Physics 1· difficulty 1/5

A 0.20 kg0.20~\text{kg} ball at 5 m/s5~\text{m/s} is struck and rebounds at 5 m/s5~\text{m/s} (opposite direction). The impulse is

  • A

    00

  • B

    10 N⋅s10~\text{N·s}

  • C

    1 N⋅s1~\text{N·s}

  • D

    2 N⋅s2~\text{N·s}

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Explanation

J=Δp=m(vf−vi)=0.20(5−(−5))=2 N⋅sJ = \Delta p = m(v_f - v_i) = 0.20(5 - (-5)) = 2~\text{N·s}.

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