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Linear Momentum

AP Physics 1· difficulty 2/5

Two masses approach each other on a frictionless 1-D track: m1=2 kgm_1 = 2~\text{kg} at +5 m/s+5~\text{m/s} and m2=3 kgm_2 = 3~\text{kg} at −2 m/s-2~\text{m/s}. After they collide and stick, the common velocity is

  • A

    −0.4 m/s-0.4~\text{m/s}

  • B

    +1.4 m/s+1.4~\text{m/s}

  • C

    +5 m/s+5~\text{m/s}

  • D

    +0.8 m/s+0.8~\text{m/s}

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Explanation

pi=(2)(5)+(3)(−2)=10−6=4p_i = (2)(5) + (3)(-2) = 10 - 6 = 4. v′=4/5=0.8 m/sv' = 4/5 = 0.8~\text{m/s}.

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