AP Physics 1 · Topic 4.1

Linear Momentum Practice

Part of Linear Momentum.(TOP-4.A)

Practice questions

3

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Sample questions

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  1. Sample 1difficulty 1/5

    A 0.50 kg0.50~\text{kg} ball moves at 12 m/s12~\text{m/s}. What is the magnitude of its momentum?

    • A

      24 kg⋅m/s24~\text{kg·m/s}

    • B

      6.0 kg⋅m/s6.0~\text{kg·m/s}

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    • C

      12 kg⋅m/s12~\text{kg·m/s}

    • D

      36 kg⋅m/s36~\text{kg·m/s}

    Why

    p=mv=(0.50)(12)=6.0 kg⋅m/sp = m v = (0.50)(12) = 6.0~\text{kg·m/s}.

  2. Sample 2difficulty 2/5

    A 0.5 kg0.5~\text{kg} ball moving east at 4 m/s4~\text{m/s} has momentum

    • A

      2 kg⋅m/s2~\text{kg·m/s} east

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    • B

      8 kg⋅m/s8~\text{kg·m/s} east

    • C

      2 kg⋅m/s2~\text{kg·m/s} west

    • D

      0.5 kg⋅m/s0.5~\text{kg·m/s} east

    Why

    p=mv=2.0 kg⋅m/sp = m v = 2.0~\text{kg·m/s} in the direction of motion.

  3. Sample 3difficulty 2/5

    Two masses approach each other on a frictionless 1-D track: m1=2 kgm_1 = 2~\text{kg} at +5 m/s+5~\text{m/s} and m2=3 kgm_2 = 3~\text{kg} at 2 m/s-2~\text{m/s}. After they collide and stick, the common velocity is

    • A

      0.4 m/s-0.4~\text{m/s}

    • B

      +1.4 m/s+1.4~\text{m/s}

    • C

      +5 m/s+5~\text{m/s}

    • D

      +0.8 m/s+0.8~\text{m/s}

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    Why

    pi=(2)(5)+(3)(2)=106=4p_i = (2)(5) + (3)(-2) = 10 - 6 = 4. v=4/5=0.8 m/sv' = 4/5 = 0.8~\text{m/s}.