Linear Momentum

AP Physics 1· difficulty 1/5

A 0.50 kg0.50~\text{kg} ball moves at 12 m/s12~\text{m/s}. What is the magnitude of its momentum?

  • A

    24 kg⋅m/s24~\text{kg·m/s}

  • B

    6.0 kg⋅m/s6.0~\text{kg·m/s}

    check_circle
  • C

    12 kg⋅m/s12~\text{kg·m/s}

  • D

    36 kg⋅m/s36~\text{kg·m/s}

Explanation

p=mv=(0.50)(12)=6.0 kg⋅m/sp = m v = (0.50)(12) = 6.0~\text{kg·m/s}.

Want 10 more like this — adaptive to your weak spots?

Related questions