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Representing Motion

AP Physics 1· difficulty 2/5

An object's velocity is constant at −4 m/s-4~\text{m/s} for 5 s5~\text{s}. If it started at x0=+10 mx_0 = +10~\text{m}, where is it at t=5 st = 5~\text{s}?

  • A

    +10 m+10~\text{m}

  • B

    −20 m-20~\text{m}

  • C

    −30 m-30~\text{m}

  • D

    −10 m-10~\text{m}

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Explanation

Δx=vt=(−4)(5)=−20 m\Delta x = v t = (-4)(5) = -20~\text{m}. xf=10−20=−10 mx_f = 10 - 20 = -10~\text{m}.

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